Calculus

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Evaluate the integral.

The integral from the square root of three over three to the square root of three of the function 6/(t^2+1)

  • Calculus -

    This is one of your standard integrals:

    ∫dx/(x^2+1) = arctan(x)

    now, what angle θ has tanθ = √3/3?
    θ = pi/6

    Now go and crank on it. If you get stuck, come on back.

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