NaOH+H2SO4-> H2o+Na2SO4?
How many moles of NaOH required to neutralize 1 mole H2SO4?
Have you considered balanceing the equation first? Great minds do that first.
1. Balance the equation.
2. mols NaOH = M x L = ?
3. Convert mols NaOH to mols H2SO4.
4. M H2SO4 = moles H2SO4/L H2SO4.
5. 2 moles
I believe
To determine the number of moles of NaOH required to neutralize 1 mole of H2SO4, you need to consider the stoichiometric ratio between NaOH and H2SO4 in the balanced chemical equation.
The balanced equation for the reaction between NaOH and H2SO4 is:
2NaOH + H2SO4 → 2H2O + Na2SO4
From this equation, you can see that for every 1 mole of H2SO4, you need 2 moles of NaOH to fully neutralize it.
Therefore, to find the number of moles of NaOH required, you simply multiply the number of moles of H2SO4 by the stoichiometric coefficient ratio:
Number of moles of NaOH = 2 × Number of moles of H2SO4
In this case, since you have 1 mole of H2SO4, you would need:
Number of moles of NaOH = 2 × 1 = 2 moles of NaOH
So, 2 moles of NaOH are required to neutralize 1 mole of H2SO4.