at the airport the new run way will be parallel to a highway. on the scale drawing of the airport the equation that represents the highway is 6y=8x-11. what is the equation for the runway
6y = 8x-11.
8x - 6y = 11.
m = -A/B = -8/-6 = 4/3.
Y-int = C/B = -11/6
Y = mx + b.
Let b = 2:
Y = (4/3)X + 2.
3y = 4x + 6.
Eq: 4x-3y = -6.
To find the equation for the runway, we need to understand that the runway is parallel to the highway. In a plane, parallel lines have the same slope.
The given equation for the highway is 6y = 8x - 11. To determine the slope of this equation, let's rewrite it in slope-intercept form (y = mx + b), where m represents the slope.
Divide the entire equation by 6:
y = (8/6)x - 11/6
Simplify:
y = (4/3)x - 11/6
The slope of the highway equation is 4/3. Therefore, the slope of the runway will also be 4/3.
Now we need the y-intercept (b) for the runway equation. In parallel lines, the y-intercept may be different. To find it, we need another piece of information.
If you have the coordinates of a point on the runway or any additional information, please provide it so that we can determine the y-intercept and complete the equation for the runway.