Write a balanced equation showing the solubility equilibrium reaction of solid calcium hydroxide??
Ca(OH)2(s) + H2O ==> Ca^2+(aq) + 2OH^-(aq)
Is an endothermic reaction more likely to be spontaneous at a higher or lower temperature??
The solubility equilibrium reaction of solid calcium hydroxide (Ca(OH)2) can be represented by the following balanced equation:
Ca(OH)2 (s) ⇌ Ca^2+ (aq) + 2OH^-(aq)
To write a balanced equation showing the solubility equilibrium reaction of solid calcium hydroxide (Ca(OH)2), you need to consider that it is an ionic compound, meaning it dissociates into its constituent ions in water. The solubility equilibrium can be represented as follows:
Ca(OH)2 (s) ⇌ Ca2+ (aq) + 2OH− (aq)
In this equation, the solid calcium hydroxide (Ca(OH)2) dissociates into calcium ions (Ca2+) and hydroxide ions (OH−) in the aqueous (aq) phase. Note that the (s) represents the solid state, while the (aq) represents the aqueous state.
Keep in mind that this equation represents the dissolution of calcium hydroxide, so the reaction moves in both directions, meaning it is in equilibrium.