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Select the equation that solves this problem:
Eight coins (dimes and nickels) are worth 60 cents. How many dimes are
there?
a. 10d + 25(11 - d) = 170
b. 10d + 25(8 - d) = 170
c. 10d + 5(8 - d) = 60
d. 10d + 5(11 - d) = 60

  • math -

    C.

    d = the number of dimes, while 8-d equals the numbers of nickels, if you multiply the number of each coins by their value ( 10 cents or 5 cents ) and add them, you should get 60

  • math -

    A nickel is worth 5 cents and a dime is worth 10 cents.


    n = numbers of a nickels

    d = numbers of a dimes


    n + d = 8

    n = 8 - d


    Value of money :

    10 ¢ * d + 5 ¢ * n = 60 ¢

    10 d + 5 n = 60

    10 d + 5 ( 8 - d ) = 60

    Equation c.

    10 d + 5 ( 8 - d ) = 60

    10 d + 5 * 8 + 5 * ( - d ) = 60

    10 d + 40 - 5 d = 60

    5 d + 40 = 60

    5 d = 60 - 40

    5 d = 20 Divide both sides by 5

    d = 20 / 5

    d = 4


    n = 8 - d = 8 - 4 = 4


    4 dimes and 4 nickels


    4 * 10 ¢ + 4 * 5 ¢ =

    40 ¢ + 20 ¢ = 60 ¢

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