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What amperage is required to plate out .250 mol Cr from a Cr+3 solution in a period of 8.00 h?

  • Chemistry -

    96,485 C will plate 1/3 mol Cr^3+ or 0.333 mol Cr^3+. You want 0.25. You will need 96,485 C x 0.25/0.333 = ?
    C = A x sec
    ?C = A x 8 hr x (60min/hr) x (60sec/min)
    Solve for A.

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