Volume of 1200 L of helium at 4000 Pa is heated from 45.0°C to 75.0°C increasing the pressure to 6000 Pa. What is the resulting volume of gas?
use Ideal Gas Law Equation
p1V1/T1 = p2V2/T2
p1•V1/T1 = p2•V2/T2
V1 =1200 L =1200•10^-3 m^3
T1 =273 +45 = 318 K
T2 =273 +75 = 348 K
V2 = p1•V1•T2/p2•T1
To determine the resulting volume of gas, we can use the combined gas law equation:
P1V1 / T1 = P2V2 / T2
Where:
P1 = initial pressure of the gas (4000 Pa)
V1 = initial volume of the gas (1200 L)
T1 = initial temperature of the gas in Kelvin (45.0°C + 273.15 = 318.15 K)
P2 = final pressure of the gas (6000 Pa)
V2 = final volume of the gas (unknown)
T2 = final temperature of the gas in Kelvin (75.0°C + 273.15 = 348.15 K)
Substituting the given values into the equation, we get:
(4000 Pa)(1200 L) / 318.15 K = (6000 Pa)(V2) / 348.15 K
Now, we can solve for V2:
(4000 Pa)(1200 L)(348.15 K) = (6000 Pa)(V2)(318.15 K)
V2 = [(4000 Pa)(1200 L)(348.15 K)] / [(6000 Pa)(318.15 K)]
V2 ≈ 311.53 L
Therefore, the resulting volume of the gas is approximately 311.53 L.