Math
posted by Nathan .
Factor over {complex numbers}
9x^2 + 49

how about ...
(3x + 7i)(3x  7i) ?
check:
(3x + 7i)(3x  7i)
= 9x^2 49i^2, but i^2= 1
= 9x^2  49(1)
= 9x^2 + 49
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