Calculus and vectors

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A plane, π, has 3x-5z+3=0 as its Cartesian equation. Determine the Cartesian equation of a plane that is perpendicular to π and contains the point P(2,9,-3)

  • Calculus and vectors -

    the normal of the given plane is
    (3,0,-5) which is then the direction of your line

    A vector equation of that line is
    r = (x,y,z) = (2,9,-3) + t(3,0,-5) where t is your parameter

    x = 2 + 3t ---> t = (x-2)/3
    y = 9 + 0t ---> y = 9
    z = -3 - 5t --> t = (z+3)/-5

    so

    (x-2)/3 = (z+3)/-5 , y = 9

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