according to american insurance companies a driver will travel 12,000miles in a single year.gasoline may be taken as primarily C8H18,octane, and the reaction with dioxygen is given below.the driver's vehicle gets 25.0miles per gallon.the density of octane is 0.703g/ml.
2C8H18 +25O2=16CO2+18H2O
how much gasoline in gallon is used in one year.
how much gasoline in grams is used in one year.
how much CO2 in grams in grams is produced in a single year?how many pounds of CO2 are produced
A lot of work for one question. How much do you know how to do? What exactly do you not understand about this question?
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To find the amount of octane needed in gallons for a driver to travel 12,000 miles in a year, we need to use dimensional analysis. Here's how you can calculate it step by step:
Step 1: Calculate the number of gallons needed for 12,000 miles.
We know that the driver's vehicle gets 25.0 miles per gallon. So, dividing the total distance (12,000 miles) by the miles per gallon (25.0) will give us the number of gallons needed:
12,000 miles / 25.0 miles per gallon = 480 gallons
Step 2: Convert gallons to milliliters.
Since the density of octane is given in grams per milliliter, we need to convert gallons to milliliters. We can do this by using the conversion factor:
1 gallon = 3,785.41 milliliters
So, multiply the number of gallons (480) by the conversion factor to get the volume in milliliters:
480 gallons * 3,785.41 milliliters per gallon = 1,815,868.8 milliliters
Step 3: Convert milliliters to grams.
We know that the density of octane is 0.703 grams per milliliter. Multiply the volume in milliliters (1,815,868.8) by the density (0.703) to get the mass in grams:
1,815,868.8 milliliters * 0.703 grams per milliliter = 1,276,185.18 grams
Step 4: Convert grams to moles.
The molar mass of octane (C8H18) can be calculated using the atomic masses of carbon (C) and hydrogen (H) from the periodic table. The molar mass of C is 12.01 g/mol, and the molar mass of H is 1.01 g/mol. Octane has 8 carbon atoms and 18 hydrogen atoms, so the molar mass of octane is:
(8 * 12.01 g/mol) + (18 * 1.01 g/mol) = 114.23 g/mol
Divide the mass in grams (1,276,185.18) by the molar mass (114.23) to get the number of moles:
1,276,185.18 grams / 114.23 g/mol = 11,159.25 moles
Step 5: Convert moles to the stoichiometry of the balanced reaction.
The balanced equation shows that 2 moles of octane react with 25 moles of oxygen to produce 16 moles of carbon dioxide and 18 moles of water.
Since the molar ratio between octane and carbon dioxide is 2:16, we can use this ratio to find the moles of carbon dioxide produced:
11,159.25 moles of octane * (16 moles of CO2 / 2 moles of octane) = 89,274 moles of CO2
Step 6: Convert moles of carbon dioxide to mass of carbon dioxide.
The molar mass of carbon dioxide (CO2) can be calculated using the atomic masses of carbon and oxygen. The molar mass of C is 12.01 g/mol, and the molar mass of O is 16.00 g/mol. Carbon dioxide has 1 carbon atom and 2 oxygen atoms, so the molar mass is:
(1 * 12.01 g/mol) + (2 * 16.00 g/mol) = 44.01 g/mol
Multiply the moles of carbon dioxide (89,274) by the molar mass (44.01) to get the mass in grams:
89,274 moles * 44.01 g/mol = 3,927,155.74 grams
Step 7: Convert grams to kilograms.
To convert grams to kilograms, divide the mass in grams (3,927,155.74) by 1000:
3,927,155.74 grams / 1000 = 3,927.16 kilograms
So, according to the stoichiometry of the reaction and the given information, the driver will need approximately 3,927.16 kilograms of octane to travel 12,000 miles in a year.