physicsHS
posted by lenny .
Just as a car tops a 49 meter high hill with a speed of 77 km/h it runs out of gas and coasts from there, without friction or drag. How high, to the nearest meter, will the car coast up the next hill?
plzzz help!

77 km/h = 21.4 m/s
m•g•h+m•v^2/2 = m•g•H
H = h+v^2/2•g = 49 +(21.4)^2/2•9.8 =72.4 m
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