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solve the system of linear equations

2x+2y=1
3x-y=6

thanks

  • math -

    2x+2y=1
    This one is obvious. Just divide the coefficients by each other, and take any inequalities and subtract them by themselves.

    3x-y=6
    This one is a bit tougher. First, you need to square everything. Then add 4, subtract 7, and take the square root of it all. It may not seem right, but it IS fairly complex.

  • math -

    2x+2y=1
    6x-2y=12

    -4x=-11
    x= 11/4

    2(11/4)+2y=1
    1-22/4=2y
    -18/4=2y
    -18/8=y

  • math -

    1st equation ---> 2x + 2y = 1
    2nd equation times 2 ---> 6x - 2y = 12
    add them
    8x = 13
    x = 13/8

    sub into 1st:
    2(13/8+ 2y = 1
    2y = 1 - 13/4
    2y = -9/4
    y = -9/8

    x = 13/8 , y = -9/8

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