algebra
posted by lizzy .
. A boy is sitting in his red wagon at the top of a hill, holding onto a tree to keep from rolling down the hill. The distance from the top of the hill to the bottom is 41 meters. He pushes off from the tree at a starting velocity of 2 m/s, and then gravity accelerates the wagon at a constant rate of 2 m/s2. How long will it take him to reach the bottom of the hill (round to the nearest hundredth)?

h(t) = 41 2t  t^2
h(t) = 0 when t = √42  1 = 5.48