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You have a 1 L container of a gas O 2 at 20°C and 1 atm. Subtracting the weight of the container, what is the mass of the gas?

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    PV=nRT *n = #mol*
    n=PV/RT
    (1atm*1L)/(0.0821(L*atm/K*mol)*293K)=n
    0.42=n

    1mol O2= 32g O2 (according to the periodic table)
    0.42mol*32g = 13.44g O2

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