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A voltaic cell is constructed that is based on the following reaction.
Sn2+(aq) + Pb(s) -> Sn(s) + Pb2+(aq)
(a) If the concentration of Sn2+ in the cathode half-cell is 1.80 M and the cell generates an emf of +0.219 V, what is the concentration of Pb2+ in the anode half-cell?

(b) If the anode half-cell contains [SO42−] = 19.08 M in equilibrium with PbSO4(s), what is the Ksp of PbSO4?


    Ecell = Eocell - 0.0592/2*log Q where
    Q = [products]/[reactants]
    Substitute into the equation and solve for the one unknown.

    b. After you determine (Pb^2+) in the half cell, then (Pb^2+)(SO4^2-) = Ksp

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