posted by Debbie .
Which is the oxidizing agent in the reaction below.
Cr2O72- + 6S2O32- +14H+ > 2Cr3+ + 3S4O62- +7H20
I believe it's D or is it C not 100% sure please help. THANKS
The oxidizing agent is the substance that is reduced. I assume you made an typo in C and it should be Cr2O7^2-.