How do I write the skeleton equation then balance the following (step by step):
hydrogen+bromine---> hydrogen bromide
H2 + Br2 ==> 2HBr
To write and balance the skeleton equation for the reaction between hydrogen and bromine to form hydrogen bromide, follow these step-by-step instructions:
Step 1: Write the skeleton equation
Start by writing the reactants on the left-hand side of the arrow and the products on the right-hand side. The reactants are hydrogen (H2) and bromine (Br2), and the product is hydrogen bromide (HBr).
So the skeleton equation is: H2 + Br2 ---> HBr
Step 2: Balance the skeletal equation
Next, balance the equation by making sure that the number of atoms on each side of the equation is the same. In this case, we need to balance the number of hydrogen (H) and bromine (Br) atoms.
Start by counting the number of hydrogen atoms on each side of the equation:
Reactants:
H2 + Br2
There are 2 hydrogen atoms on the left-hand side (2H2).
Products:
HBr
There is only 1 hydrogen atom on the right-hand side.
Since the number of hydrogen atoms is not balanced, we need to add a coefficient in front of the product to balance it. Let's add a 2 in front of the HBr to have 2 hydrogen atoms:
H2 + Br2 ---> 2HBr
Now let's check the number of bromine atoms:
Reactants:
H2 + Br2
There are 2 bromine atoms on the right-hand side.
Products:
2HBr
There are 2 bromine atoms on the left-hand side (2HBr).
Now the number of bromine atoms is balanced.
Therefore, the balanced equation for the reaction between hydrogen and bromine to form hydrogen bromide is:
H2 + Br2 ---> 2HBr