algebra
posted by kathy .
The width of a rectangle is 3 cm less than the length. The area of the rectangle is 54 square cm. Find the width and length of the rectangle.

I'll work with the width, since the letter l and the digit 1 look similar.
if the length is 3 more than the width,
w(w+3) = 54
w^2 + 3w = 54
w^2 + 3w  54 = 0
(w+9)(w6) = 0
w=6 (can't have negative width)
the rectangle is 6x9
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