Algebra

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R varies jointly as r and B^2. When r=3, and B=3 R=135. Find R when r is 1
and B=10.

  • Algebra -

    R = krB^2
    135 = k(3)(3^2) = 27k
    k = 5

    So, R(r,B) = 5rB^2
    R(1,10) = 5(1)(100) = 500

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