Consider the combustion of glucose:
C6H12O6(s) + 6O2(g) <---> 6CO2(g) + 6H2O(g)
H = −3 kJ/mol
Which condition
I) Adding more carbon dioxide;
II) Performing the reaction in a hotter environment;
III) Decreasing the pressure of the system;
IV) Adding a reagent that irreversibly binds
glucose and prevent it from further reactions.
would result in the production of additional water vapor?
Two things to remember about Le Chatelier's Principle.
1. Always true--When a system in equilibrium is subjected to a stress it will shift to undo what we've done.
1a. True in gaseous systems--Increased pressure will shift the equilibrium to the side with the fewer moles of gas.
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I ans IV
To determine which condition would result in the production of additional water vapor in the combustion of glucose, we need to consider the balanced chemical equation and identify the components that directly contribute to the formation of water.
In the given balanced equation:
C6H12O6(s) + 6O2(g) ↔ 6CO2(g) + 6H2O(g)
We can see that 6 moles of water (H2O) are formed for every 1 mole of glucose (C6H12O6) that reacts. Based on this information, let's analyze each condition:
I) Adding more carbon dioxide (CO2):
Adding more carbon dioxide (CO2) would not directly affect the production of water vapor. The stoichiometry of the reaction states that water is produced based on the moles of glucose, not the moles of carbon dioxide.
II) Performing the reaction in a hotter environment:
Increasing the temperature of the reaction would generally increase the rate of reaction, but it wouldn't directly contribute to the production of additional water vapor. The formation of water is determined by the initial amount of glucose present, not the temperature.
III) Decreasing the pressure of the system:
The production of water vapor is not directly dependent on the pressure of the system. Changes in pressure would primarily affect the equilibrium position of the reaction, but it would not alter the stoichiometry or the amount of water produced.
IV) Adding a reagent that irreversibly binds glucose and prevents further reactions:
If a reagent is added that irreversibly binds glucose and prevents further reactions, it would decrease the amount of glucose available for the combustion reaction. Since the reaction requires glucose to produce water, adding a reagent that eliminates glucose would result in a decreased production of water vapor.
Therefore, none of the mentioned conditions (I, II, III, IV) would result in the production of additional water vapor. The amount of water produced is solely determined by the amount of glucose available for combustion.