# Chemistry

posted by .

In the presence of an alkali, Cl2 reacts to form Cl- and ClO3- , as follows:

3 Cl2(g) + 6 OH−(aq) → 5 Cl−(aq) + ClO3−(aq) + 3 H2O(l)

a. Calculate the oxidation number for chlorine in each of the species.

b. Write a half equation for the formation of Cl- from Cl2

c. Write a half equation for the formation of ClO3- from Cl2

d. Name and explain what type of reaction this is.

e. Identify which species is being reduced

f. identify which is the oxidising agent

• Chemistry -

There is no point in me redoing those parts you understand (and I assume you know how to do parts of it). What is it you're having trouble with?

• Chemistry -

c, d, e and f are where I am struggling.

• Chemistry -

c.
12OH^- + Cl2 ==> 2ClO3^- + 10e + 6H2O
(Note: This is twice what you will need when you balance the entire equation so you just divide all of the coefficients by 2. That will leave just Cl (and not Cl2 but when you add it to the other half cell--likewise divided by 2--the Cl from the oxidized half cell and the Cl from the reduced half cell you get the Cl2 you're familiar with.)
Here is a link that shows how to do this as well as most any other item regarding redox equations.
http://www.chemteam.info/Redox/Redox.html

e. Reduction is the gain of electrons.Which half cell gained electrons?
f. The oxidizing agent is the substance being reduced.
d. What type reaction? It's a redox equation; however, when the same substance is both oxidized and reduced it is still a redox reaction but it is given a special name of disproportionation.

By the way, when I have an equation like this, I just separate them into to the two half cells, balanced them with Cl2 ==> 2Cl^- and
Cl2 ==> ClO3^-, then add the two half cells and divide all of the coefficients by 2.

• Chemistry -

Thank you, thank you thank you

## Similar Questions

1. ### Chemistry

In the presence of an alkali, Cl2 reacts to form Cl- and ClO3- , as follows: 3 Cl2(g) + 6 OH−(aq) → 5 Cl−(aq) + ClO3−(aq) + 3 H2O(l) a. Calculate the oxidation number for chlorine in each of the species. b. …
2. ### Chemistry

In the redox conversion of CO to CO2− 3 , the oxidation number of C goes from (−2, 0, +2) to (−4, −2, +4, +6). Recall that the oxidation number of oxygen is typically −2. 1. +2; +6 2. −2; −4 …
3. ### Chemistry

Balance the following equation. (for a balanced eq. aA + bB → cC + dD, enter your answer as the integer abcd) MnO4−(aq) + SO32−(aq) + H+(aq) → Mn2+(aq) + SO42−(aq) + H2O(l) i got 2525 and its going in …
4. ### CHEMISTRY HELP ASAP

Balance the following equation. (for a balanced eq. aA + bB → cC + dD, enter your answer as the integer abcd) MnO4−(aq) + SO32−(aq) + H+(aq) → Mn2+(aq) + SO42−(aq) + H2O(l) i got 2525 and its going in …
5. ### biology

Given the part of the molecule shown below, can the underlined atom participate in a hydrogen bond with an approriate bonding partner?
6. ### CHEMISTRY

Balance the following equation. (for a balanced eq. aA + bB → cC + dD, enter your answer as the integer abcd) CrO42−(aq) + H2O(l) + HSnO2− → CrO2−(aq) + OH−(aq) + HSnO3−(aq)
7. ### Chemistry

Dr.Bobb222 please help balance the following oxidation-reduction reactions, which occur in acidic solution, using the half-reaction method. (Use the lowest possible coefficients. Include states-of-matter under the given conditions …
8. ### Chem

Write the formulas of the compounds formed by Pb4+ with the following anions: CN−, ClO3−, SO42−, H2PO4−.