Chem

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How many sodium ions are present in 825 ml of 0.825 M Na2SO4?

  • Chem -

    1L of 1M solution contains 1 mole

    .825L of .825M contains .68 moles of Na2SO4

    Each mole contains 2 Na ions

    2*.68 * 6.02*10^23 = 8.2 * 10^23 Na ions

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