6/?=18/?=?/12 (fractions)

if you have 6/24 and 18/72 and 3/12 it all reduces to 1/4

thankyou

To solve this problem, we need to find the missing values in the fractions. Let's break it down step by step.

1. First, let's tackle the expression 6/? = 18/?.
- We know that the numerator for the first fraction is 6, and the numerator for the second fraction is 18. Since the numerators are the same, we can set up an equation: 6/? = 18/?.
- Now, cross-multiply: 6 * ? = 18 * ?.
- This simplifies to 6 = 18. However, this is not true, which means there is no solution for this equation. Therefore, there is no specific value for "?", or the denominator in this case.

2. Next, let's consider the expression 18/? = ?/12.
- The numerator for the first fraction is 18, and the denominator for the second fraction is 12. Let's set up the equation: 18/? = ?/12.
- Once again, we cross-multiply: 18 * 12 = ? * ?.
- This simplifies to 216 = ?^2.

Since "?^2 = 216", we need to find a number whose square is 216. By taking the square root of both sides, we find that "? = ±√216". Simplifying further, "? = ±6√6".

Therefore, the solution to the equation is "? = ±6√6".