How would you solve for 'a'?
(1/a) - (1/b) = c
would you use the LCD???
1 / a - 1 / b = c
1 / a = c - 1 / b
1 / a = c b / b - 1 / b
1 / a = ( c b - 1 ) / b
Reciprocal :
a = b / ( c b - 1 )
(1/a) - (1/b) = c
would you use the LCD???
1 / a = c - 1 / b
1 / a = c b / b - 1 / b
1 / a = ( c b - 1 ) / b
Reciprocal :
a = b / ( c b - 1 )