MathLog#4
posted by Serena .
How would you solve for 'a'?
(1/a)  (1/b) = c
would you use the LCD???

1 / a  1 / b = c
1 / a = c  1 / b
1 / a = c b / b  1 / b
1 / a = ( c b  1 ) / b
Reciprocal :
a = b / ( c b  1 )
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