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How would you solve for 'a'?
(1/a) - (1/b) = c

would you use the LCD???

  • MathLog#4 -

    1 / a - 1 / b = c

    1 / a = c - 1 / b

    1 / a = c b / b - 1 / b

    1 / a = ( c b - 1 ) / b

    Reciprocal :

    a = b / ( c b - 1 )

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