posted by Nicholas .
I balanced an equation between lead(II) nitrate and potassium sulfate and ended up with:
Pb(NO3)2 + K2SO4 --> PbSO4 + 2 KNO3
If 0.87 moles of potassium sulfate react with an excess amount of lead(II) nitrate, how many moles of lead(II) sulfate would be formed?
I know I start with 0.87 moles K2SO4, but I am confused on the stoichiometry part to solve the problem.
Here is a worked example that shows exactly how to do the conversion from mols of one material to mols of another.
mm(zn)=65g/mol m(hcl)=36.5g/mol m(h2)=2g/mol