Physical Science

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what amount of energy in calories would it take to bring 20 grams of solid ice at negative twelve degrees celsius to liquid water at 100 degrees celsius?

  • Physical Science -

    Q = ΔU1 + ΔU2 + ΔU3 =
    =c1•m •ΔT1 +λ•m + c2•m •ΔT2 =
    =20•10^-3•(2.060•10^3• 12 + 335•10^3 + 4.183•10^3•100) =
    =15560 J
    (c1, c2 –specific heats of ice and water, λ –heat of fusion of ice)

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