According to the following reaction, how many grams of zinc hydroxide will be formed upon the complete reaction of 29.8 grams of water with excess zinc oxide?

ZnO (s) + H2O (l) Zn(OH)2 (aq)

ZnO (s) + H2O (l) ---> Zn(OH)2 (aq)

same number of moles of Zn(OH)2 as of water

water = 2 + 16 = 18 grams/mol
so
29.8/18 = 1.66 moles of H2O and of Zn(OH)2

Zn = 65
2O = 32
2H = 2
-------
99 grams/mole
99*1.66 = 154 grams Zn(oh)2

To find the number of grams of zinc hydroxide formed, you need to follow these steps:

Step 1: Determine the molar mass of water (H2O) and zinc oxide (ZnO).

The molar mass of water (H2O) is calculated by adding the atomic mass of hydrogen (H) and the atomic mass of oxygen (O):
Molar mass of H2O = 2 * atomic mass of H + atomic mass of O

The atomic mass of hydrogen is approximately 1 gram/mol, and the atomic mass of oxygen is approximately 16 grams/mol.
Molar mass of H2O = 2 * 1 g/mol + 16 g/mol = 18 g/mol

The molar mass of zinc oxide (ZnO) can be calculated by adding the atomic mass of zinc (Zn) and the atomic mass of oxygen (O):
Molar mass of ZnO = atomic mass of Zn + atomic mass of O

The atomic mass of zinc is approximately 65.38 grams/mol, and the atomic mass of oxygen is approximately 16 grams/mol.
Molar mass of ZnO = 65.38 g/mol + 16 g/mol = 81.38 g/mol

Step 2: Use stoichiometry to determine the molar ratio between zinc oxide (ZnO) and zinc hydroxide (Zn(OH)2).

From the balanced equation, you can see that the stoichiometric ratio between ZnO and Zn(OH)2 is 1:1. This means that for every 1 mole of ZnO, you get 1 mole of Zn(OH)2.

Step 3: Convert the given mass of water to moles using the molar mass of water.

Moles of H2O = given mass of H2O / molar mass of H2O
Moles of H2O = 29.8 g / 18 g/mol ≈ 1.655 moles

Step 4: Use the stoichiometric ratio to find the moles of Zn(OH)2.

Since the stoichiometric ratio between ZnO and Zn(OH)2 is 1:1, the moles of Zn(OH)2 will be equal to the moles of H2O.

Moles of Zn(OH)2 = Moles of H2O ≈ 1.655 moles

Step 5: Convert the moles of Zn(OH)2 to grams using the molar mass of Zn(OH)2.

Mass of Zn(OH)2 = Moles of Zn(OH)2 x Molar mass of Zn(OH)2
Mass of Zn(OH)2 = 1.655 moles x 81.38 g/mol ≈ 134.82 grams

Therefore, approximately 134.82 grams of zinc hydroxide will be formed upon the complete reaction of 29.8 grams of water with excess zinc oxide.

To determine the number of grams of zinc hydroxide formed, we need to use stoichiometry and molar mass calculations. Here is a step-by-step explanation of how to solve this problem:

Step 1: Write the balanced chemical equation.
The balanced equation is: ZnO (s) + H2O (l) -> Zn(OH)2 (aq)

Step 2: Identify the known and unknown quantities.
Known: Mass of water = 29.8 grams
Unknown: Mass of zinc hydroxide (Zn(OH)2)

Step 3: Convert the mass of water to moles.
To convert mass to moles, we need to use the molar mass of water. The molar mass of water (H2O) is 18.015 g/mol.

moles of water = mass / molar mass
moles of water = 29.8 g / 18.015 g/mol ≈ 1.652 mol

Step 4: Determine the stoichiometric ratio.
From the balanced equation, we can see that the ratio between ZnO and Zn(OH)2 is 1:1. This means that for every 1 mol of ZnO, 1 mol of Zn(OH)2 is formed.

Step 5: Convert moles of water to moles of Zn(OH)2.
Since the stoichiometric ratio is 1:1, the moles of Zn(OH)2 formed will be the same as the moles of water.

moles of Zn(OH)2 = moles of water ≈ 1.652 mol

Step 6: Convert moles of Zn(OH)2 to grams.
To convert moles to grams, we need to use the molar mass of Zn(OH)2. The molar mass of Zn(OH)2 is 99.388 g/mol.

mass of Zn(OH)2 = moles of Zn(OH)2 × molar mass
mass of Zn(OH)2 = 1.652 mol × 99.388 g/mol ≈ 163.97 grams

Therefore, approximately 163.97 grams of zinc hydroxide will be formed upon the complete reaction of 29.8 grams of water with excess zinc oxide.

the above is wrong, its 2*16 not 2+16