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10.0mL 0.5M sulfuric acid can neutralize what volume of 0.5M ammonium hydroxide?

H2SO4 + 2NH4OH -> (NH4)2SO4 + 2H2O

so, 1 mole of H2SO4 reacts with 2moles NH4OH

So, how many moles in 10ml of .5M H2SO4?
.01L * .5moles/L = .05 moles H2SO4

So, how many moles of NH4OH will be used?

I might point out here that it has been shown that NH4OH does not exist. It is convenient to write NH3(aq) + H2O ==> NH4OH ==> NH4^+ + OH^- but the intermediate is not there.

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