algebra
posted by scott .
tugboat goes 160 miles upstream in 10 hours. The return trip downstream takes 5 hours. Find the speed of the tugboat without a current and the speed of the current.
speed of tugboat is
speed of the current is

speed of tugboat in still water  x
speed of current  y
the key is that the distance is the same
so 10(xy) = 160 or
x  y = 16
and 5(x+y) = 160
x+y = 32
add them:::
2x = 48
x = 24 , then y = 8