Probability
posted by Kay .
Jolie has 6 quarters, 6 dimes, 4 nickels, and 10 pennies in her coin purse. If two coins are drawn at random without replacement, what is the probability of drawing a quarter on the first draw and a nickel on the second draw?

Total = 6+6+4+10=26 coins
First draw:
P(Q)=one of 6 quarters from 26 coins=6/26
P(N)=one of 4 nickels from remaining 25 coins = 4/25
Probability of P(Q followed by N)=P(Q)*P(N)