posted by sally
A force of magnitude Fx acting in the x-direction on a 2.50-kg particle varies in time as shown in the figure below.
(a) Find the impulse of the force.
(b) Find the final velocity of the particle if it is initially at rest
(c) Find the final velocity of the particle if it is initially moving along the x-axis with a velocity of -3.00 m/s
a. The impulse of a force is the area under the curve. The curve could be broken up into several geometric figures: a triangle, a rectangle, etc. The area of a triangle is base times height and the area of a rectangle is length times width.Use this rule for findinf I
b. I = p(f) - p(i) = mv(f) - mv(i) = mv(f),
(as v(i) = 0)
c. I = p(f) - p(i) = mv(f) - mv(i)