7.0 mL of 0.5 M acetic acid contains 0.0035 moles of acetic acid. how many moles of sodium bicarbonate are needed to react with 0.0035 moles of acetic acid?
Balance the equation.
2 H-CH3COO + 2NaHCO3 >> 2NaCH3COO +CO2 +2H2O
It appears the same number of moles.