Post a New Question

Algebra 2

posted by .

Samantha is going on a vacation for the summer and is trying to choose between two different plans. The first plan costs 450$ for 3 days at a hotel and 2 days at an amusement park. The second plan offers 5 days at the same hotel and 3 days at the amusement park for 700$. The cost of 1 day at the hotel and the amusement park is the same under both plans. How much does a 1 day trip to the amusement park cost? ((I think it's 50$)) ??

  • Algebra 2 -

    hotel costs $h/day
    park costs $p/day

    3h + 2p = 450
    5h + 3p = 700

    15h + 10p = 2250
    15h + 9p = 2100
    subtract:
    p = 150
    so, h=50

    3(50)+2(150) = 150 + 300 = 450
    5(50)+3(150) = 250 + 450 = 700

    SO, it looks like you solved the problem, but got the hotel and park switched.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question