posted by danielle .
the primary visible emissions from mercury are 404.7 nm and 435.8 nm. Calculate the frequencies for these emissions. Calculate the energy of a single photon and of a mole of photons of light with each of these wavelengths.
chem help -
c = frequency*wavelength
404.7 and 435.8 are wavelenths in nm. Convert those to m.
E = hc/wavelength for one photon.
That x 6.022E23 for a mole of photons.