posted by Anonymous .
Suppose 500 ml of a .0035 M solution of lead nitrate is reacted with sulfuric acid. What mass of lead sulfate should precipitate?
Pb(NO3)2 + H2SO4 ==> PbSO4 + 2HNO3
mols Pb(NO3)2 = M x L = ?
mols PbSO4 = moles Pb(NO3)2 from the equation which is 1:1.
mols PbSO4 x molar mass = grams.