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An object 3.28 cm tall is placed 10.5 cm in front of a mirror, which creates an upright image rant is 6.43 cm in height.
A. What is the magnification of the image?
B. What is the radius of the curvature of the mirror?

  • physics -

    A. Mag. = 6.43/3.28 = 1.96

    B. R = 2 f

    Get the focal length f from the equation

    1/do + 1/di = 1/f

    do = object distance = 10.5 cm
    di = image distance = 20.6 cm

  • physics -

    How did you get 20.6?

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