It takes an athlete 26s to runs from A to B which is east of A and 25m away. And then to C which is 32m from A. What is his velocity between town A and C? What is his velocity from B to C at a time of 5s?
To calculate velocity, we need to divide the displacement by the time it takes to cover that distance.
Velocity between town A and C:
The athlete runs from A to C, which is a total displacement of 32m (the distance from A to C). The time taken is 26s, as mentioned in the question.
Velocity = Displacement / Time
Velocity = 32m / 26s
Velocity β 1.23 m/s (rounded to two decimal places)
Velocity from B to C at a time of 5s:
To calculate the velocity from B to C at 5s, we first need to determine the displacement from B to C and the time taken.
Displacement from B to C:
The displacement from B to C is the difference in their distances from point A.
Distance from B to A is 25m, and distance from C to A is 32m.
Therefore, displacement from B to C = distance from C to A - distance from B to A
Displacement from B to C = 32m - 25m = 7m
Time taken from B to C:
Given that the time taken to run from A to B is 26s, and we want to find the velocity at 5s, we can calculate the time taken from B to C by subtracting 5s from 26s.
Time taken from B to C = 26s - 5s = 21s
Velocity from B to C at 5s:
Velocity = Displacement / Time
Velocity = 7m / 21s
Velocity β 0.33 m/s (rounded to two decimal places)