State an equation that represent this situation.

Mary invested one amount at 3% simple interest and a second amount at 9% interest ,earning $43.92 in one year.If she would have switched the amounts she would have earned $35.00.What were the 2 amounts?

.03Amount1 + .09Amount2=43.92

.09amount1 + .03Amount2=35.00

Do you have a question on how to solve this?

Yes I am not good in math

Let's assume that the amount invested at 3% interest is denoted by "x" and the amount invested at 9% interest is denoted by "y".

To begin, we can write down the formula for calculating simple interest:

Simple Interest = (Principal * Rate * Time)

For the first situation, with the amount x invested at 3% interest, the simple interest earned can be calculated as follows:

Interest_1 = (x * 0.03 * 1) = 0.03x

For the second situation, with the amount y invested at 9% interest, the simple interest earned can be calculated as follows:

Interest_2 = (y * 0.09 * 1) = 0.09y

Now, we are given two pieces of information:

1. Mary earned $43.92 in one year with the original investment amounts:

Interest_1 + Interest_2 = 43.92
0.03x + 0.09y = 43.92

2. If Mary had switched the amounts, she would have earned $35.00:

Interest_2 + Interest_1 = 35
0.09x + 0.03y = 35

Therefore, the system of equations representing this situation is:

0.03x + 0.09y = 43.92
0.09x + 0.03y = 35

By solving this system of equations, we can determine the values of x and y, which represent the two amounts Mary invested.