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Three identical uniform meter sticks are placed on the floor. The first stick lies along the y axis from y = 0.470 m to y = 1.47 m. The second stick lies along the x axis from x = 0.320 m to x = 1.32 m. The third stick is positioned so that one end is on the x axis at x = 0.690 m, and the other end is on the y axis at y = 0.724 m. Calculate the location of the center of mass of the meter sticks. Enter the x position first, then the y position.

  • physics -

    Mtotal*x=M(1/2)(0+0) + M(1/2)(1.32+.32) + M(1/2)(.690+0)

    mtotal= M+M+M so

    3*x=1/2 (....)

    solve for xcm

    for the y:
    Mtotal*y= M(1/2)(1.47+.47)+M(1/2)(0+0) + M (1/2)(.724+0)
    solve for ycm

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