physics
posted by Julia .
Three identical uniform meter sticks are placed on the floor. The first stick lies along the y axis from y = 0.470 m to y = 1.47 m. The second stick lies along the x axis from x = 0.320 m to x = 1.32 m. The third stick is positioned so that one end is on the x axis at x = 0.690 m, and the other end is on the y axis at y = 0.724 m. Calculate the location of the center of mass of the meter sticks. Enter the x position first, then the y position.

Mtotal*x=M(1/2)(0+0) + M(1/2)(1.32+.32) + M(1/2)(.690+0)
mtotal= M+M+M so
3*x=1/2 (....)
solve for xcm
for the y:
Mtotal*y= M(1/2)(1.47+.47)+M(1/2)(0+0) + M (1/2)(.724+0)
solve for ycm