A merry-go-round starts from rest and accelerates uniformly over 26.0 s to a final angular velocity of 5.50 rev/min.

Indicate your specific subject in the "School Subject" box, so those with expertise in the area will respond to the question.

To find the angular acceleration of the merry-go-round, we need to use the equation of angular acceleration:

angular acceleration (α) = (final angular velocity - initial angular velocity) / time

First, we need to convert the final angular velocity from rev/min to radians/second. Since 1 rev = 2π radians, we can use the conversion factor:

final angular velocity = 5.50 rev/min x (2π radians/1 rev) x (1 min/60 s)

Time is already given as 26.0 s.

Now, we can substitute the values into the equation:

angular acceleration (α) = (5.50 rev/min x (2π radians/1 rev) x (1 min/60 s) - 0 rad/s) / 26.0 s

Simplifying the equation:

angular acceleration (α) = (5.50 x 2π / 60 - 0) / 26.0

Thus, the angular acceleration of the merry-go-round can be calculated by evaluating this equation.