two perpendicular lines with the equations y=1/3x+9 and y=mx-3 contain the consecutive sides of a rectangle. What is the value of mx in the 2nd linear question.
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remember that if lines are perpendicular, then their slopes must be negative reciprocals of each other,
So, if the first has a slope of (1/3),
the second must have a slope of -3
A cylinder holds 100 cubic centimeters of water. If you triple the radius of the cylinder but keep the height the same, how much water would you need to fill the new cylinder? V= 3.14r^2h
To determine the value of mx in the second linear equation, we need to find the slope of the line using the given information.
The equation of a line can be written in slope-intercept form, y = mx + b, where m represents the slope of the line.
We are given two perpendicular lines with the equations:
1) y = 1/3x + 9
2) y = mx - 3
Since the lines are perpendicular, the product of their slopes will be -1. Therefore, we can set up the following equation:
(1/3) * m = -1
To solve for 'm', we can multiply both sides of the equation by 3:
(1/3) * m * 3 = -1 * 3
This simplifies to:
m = -3
Therefore, the value of mx in the second linear equation y = mx - 3 is -3.