How much applied force is needed to accelerate a 2.0 kg block of wood at 4.0m/s^2 along a rough table, against a 10 N force of friction?
Now we have two forces:
First is our force F
Second is that friction force, opposite to F so call it -10 Newtons
The block accelerates, so there is a net force (UNbalanced forces) which is net F =(F-10).
Since they are unbalanced and acceleration A results:
netF = m A
(F-10) = 2 * 4
F - 10 = 8
F = 18 N
If you do not get this PLEASE respond. You simply have to understand these three questions you asked before you go to the next chapter. This is the heart of the matter.
Thank you so much I understand now !
Excellent - Those questions are extremely important.
I`ll live in P-5 Tu-od Manticao Misamis Oriental hahaha
I was born on January 10 2003
hahaha
Well, let's see. To accelerate the block of wood against the force of friction, we need to overcome that 10 N force. Now, if only there was a superhero called "Force Man" who could easily defeat the evil villain called "Friction" with a snap of his fingers! But alas, we are stuck in the real world where we have to do a little bit of math.
To find the applied force, we can use Newton's second law, which states that force is equal to mass multiplied by acceleration (F = ma). Plugging in the values, we get:
F = 2.0 kg * 4.0 m/s^2
F = 8.0 N
So, about 8.0 N of applied force is needed to overcome the 10 N force of friction. Keep in mind, though, that this value is just a minimum requirement. If you want to be absolutely sure, you might want to add some extra force, just to clown around with friction a little bit!
To calculate the amount of applied force needed to accelerate a block of wood, we need to consider the force of friction acting on the block.
First, let's determine the magnitude of the force of friction (F_friction) acting on the block. The force of friction can be determined using the equation:
F_friction = coefficient of friction (μ) * normal force (F_normal)
However, we are given the value of the force of friction (F_friction) as 10 N, and we need to find the coefficient of friction (μ). Rearranging the equation, we have:
μ = F_friction / F_normal
Now, let's determine the normal force (F_normal) acting on the block. When the block is on a flat table, the normal force is equal to the weight (F_weight) of the block, which can be calculated as:
F_weight = mass (m) * acceleration due to gravity (g)
Given that the mass of the block (m) is 2.0 kg and the acceleration due to gravity (g) is approximately 9.8 m/s^2, we can calculate the weight:
F_weight = 2.0 kg * 9.8 m/s^2 = 19.6 N
Now, substituting the values in our first equation, we can find the coefficient of friction (μ):
μ = F_friction / F_normal = 10 N / 19.6 N ≈ 0.51
Next, let's determine the applied force (F_applied) needed to overcome the force of friction and accelerate the block. The net force (F_net) acting on the block can be calculated using Newton's second law of motion:
F_net = F_applied - F_friction
Since the block is being accelerated at 4.0 m/s^2, we can calculate the net force:
F_net = m * a = 2.0 kg * 4.0 m/s^2 = 8.0 N
Now, rearranging the equation, we can solve for the applied force (F_applied):
F_applied = F_net + F_friction = 8.0 N + 10 N = 18 N
Therefore, the applied force needed to accelerate the 2.0 kg block of wood at 4.0 m/s^2 against a force of friction of 10 N is 18 N.