Chemistry

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A 53 mL sample of a solution of sulfuric acid
is neutralized by 37 mL of a 0.18 M sodium
hydroxide solution. Calculate the molarity of
the sulfuric acid solution.
Answer in units of mol/L

  • Chemistry -

    MolarityH2SO4*2*53ml=.18*37ml

    solve for MolarityH2SO4

    Notice the 2 in the equation. You need to know what that means...

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