A 53 mL sample of a solution of sulfuric acid
is neutralized by 37 mL of a 0.18 M sodium
hydroxide solution. Calculate the molarity of
the sulfuric acid solution.
Answer in units of mol/L
MolarityH2SO4*2*53ml=.18*37ml
solve for MolarityH2SO4
Notice the 2 in the equation. You need to know what that means...