physics
posted by Melissa .
A diver is jumping straight up with 2 m/s from a 15 meter platform. Calculate the maximum height of the diver, the diver’s velocity when reaches the water, and total time to reach the water.

max height: new PE=initial KE
mgh=1/2 mv^2
h= 1/2 v^2/g
velocity at impact
KE at impact= PE lost+ initial KE
1/2 m v^2= mg(15)+1/2 m 2^2
solve for v.
Total time.
hf=hi+vi*t  4.8t^2
0=15+2t4.8t^2
solve the quadratic, use the quadratic equation to solve for t. 
Thanks bobpursely I need this for my Quantitative Biomechanics class
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