Respond to this Question
Similar Questions

Integration
Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct? 
Calculus
could anybody please explain how sec x tan x  ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx  ¡ì sec^3(x) dx What I don't understand about your question is what is ¡ì ? 
calculus
find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may have some challenging algebra to simplify it. Use the chain rule. Let y(u) = ln u u(x) = sec x + tan x … 
calculus
Use integration by parts to evaluate the integral of x*sec^2(3x). My answer is ([x*tan(3x)]/3)[ln(sec(3x))/9] but it's incorrect. u=x dv=sec^2(3x)dx du=dx v=(1/3)tan(3x) [xtan(3x)]/3  integral of(1/3)tan(3x)dx  (1/3)[ln(sec(3x))/3] … 
Calculus 12th grade (double check my work please)
2 given the curve is described by the equation r=3cos ¥è, find the angle that the tangent line makes with the radius vector when ¥è=120¨¬. A. 30¨¬ B. 45¨¬ C. 60¨¬ D. 90¨¬ not sure A or D 2.) which of the following represents … 
Calculus PLEASE check my work ,
1.) which of the following represents dy/dx when y=e^2x Sec(3x)? 
calculus
Did I do this problem right? Find the first and second derativesimplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'= xsec^2 x + tanx y"= (x)(2secx)(secxtanx)+sec^2 x + sec^2 x y"=2xsec^2 x tanx + 2 sec^2 x 
calculus (check my work please)
Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)1) dx ∫ tan(x)sec(x)[sec^4(x)sec^2(x)] … 
calculus
So I am suppose to evaulate this problem y=tan^4(2x) and I am confused. my friend did this : 3 tan ^4 (2x) d sec^ 2x (2x)= 6 tan ^4 (2x) d sec^2 (2x) She says it's right but what confuses me is she deriving the 4 and made it a three? 
Calculus AP
I'm doing trigonometric integrals i wanted to know im doing step is my answer right?