maths
posted by mwaba .
the circle is given by the equation x^2+y^2+8x7/2y=0
find
(i)coordinates of the centre and the radius
(ii)coordinates of the point where the circle crossesthe xaxis

oh well
x^2 + 8 x = y^2 + 3.5 y
x^2 + 8 x + 16 = y^2 + 3.5 y + 16
(x+4)^2 = y^2 + 3.5 y + 16
y^2  3.5 y = (x+4)^2 + 16
y^2  3.5 y + 3.0625 + (x+4)^2 = 19.0625
(x+4)^2 + (y1.75)^2 = 4.366^2
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