Calculus please help!!! double integral
posted by Sean .
Combine the following two integrals into one by sketching the region, then switching the order of integration. (sketch the region)
im gonna use the S for integral sign..because idk what else to use.
SS6ycos(x^33x)dxdy+SS6ycos(x^33x)
And the first integration limits for x are between 1 and y, for y the limits are between 0 and 1.
And the second part of the problem the limits for x are 1 to 0 and for y 0 to 1

I don't quite understand what is wanted. The first integral has us integrating x from a number to a function of y. The 2nd is over a fixed region. Both integrands are the same.
The real kicker is trying to integrate cos(x^33x). Forget it. Can't even do it numerically, since the upper limit is a function of y. I must be missing something here.
Respond to this Question
Similar Questions

maths
use an iterated integral to find area of region bounded by graphs sin(x) and cos(x) between x=pi/4 and x=5*pi/4 but using HORIZONTAL strips.(i.e dxdy is order of integration for the double integral). it has been suggested by a textbook … 
double integral
1. Sketch the region of integration & reverse the order of integration. Double integral y dydz... 1st (top=1, bottom =0)... 2nd(inner) integral (top=cos(piex), bottom=(x2)... 2. Evaluate the integral by reversing the order of integration. … 
Calculus
I'm having trouble reversing the order of integration of ∫∫dxdy from a=0 to b=2(3)^(1/2) for x and c=y^(2/6) to d=(16y^2)^(1/2) for y. I graphed the region of integration and that still doesn't really help me. i got approximately … 
double integrals
Combine the following two integrals into one by sketching the region, then switching the order of integration. (sketch the region) im gonna use the S for integral sign..lol SS6ycos(x^33x)dxdy+SS6ycos(x^33x) And the first integration … 
MATH
(a) Transform the expression (x − a)^2 + y^2 = a^2 into polar coordinates. (b) Sketch the region R bounded by the curve given in part (a). (c) Use a double integral in polar coordinates to ﬁnd the area of the region R. 
Calc 2
a. Integral (x^2)/(sqrt(1+(x^2))) Would I separate these two into 2 separate integrals? 
calc 3
1. Evaluate the given integral by making an appropriate change of variables, where R is the region in the first quadrant bounded by the ellipse 36x^2+25y^2=1. L= double integral R (4sin(144x^2+100y^2) dA. 2. Use the given transformation … 
calculus (please with steps and explanations)
consider the function f that is continuous on the interval [5,5] and for which the definite integral 0(bottom of integral sign) to 5(top of integral sign) of f(x)dx=4. Use the properties of the definite integral to evaluate each integral: … 
Calculus (double integral) PLEASE HELP!
Evaluate double integral ln((xy)/(x+y)) dy dx where the double integral region is the triangle with vertices (1,0),(4,3), (4,1). Hint: use a transformation with the Jacobian. 
Calculus  Integrals
Consider the region enclosed by the graphs of x=y^25 and x=3y^2 a)Express the area of this region by setting up an integral with respect to x b) Express the area of this region by setting up an integral with respect to y c) Find …