Algebra
posted by sherry .
Solve using the substitution method.
0.3x+0.2y=5,0.5x+0.4y=11

I would multiply each equation by 10 to get rid of those decimals
3x + 2y = 50 > 2y = 503x
5x + 4y = 110
sub 2y= 503x into the 2nd
5x + 2(503x) = 110
5x + 100  6x = 110
x = 10
x = 10
into 2y = 503x = 503(10)
2y = 80
y = 40
x = 10, y = 40