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A spherically symmetric object, with radius R = 0.50 m and mass M = 1.3 kg, rolls without slipping across a horizontal floor, with velocity V = 2.1 m/s. It then rolls up an incline with an angle of inclination θ = 25° and comes to rest a distance d = 3.0 m up the incline, before reversing direction and rolling back down. Find the moment of inertia of this object about an axis through its center of mass.

Due in an hour and a half.
I was able to follow other work but when I take 3sin(25) I get a negative number and that screws up the whole answer because you can't take the square root of a negative.

  • physics -

    KE = mv^2/2 + Iω^2/2 =
    =mv^2/2 +Iv^2/2R^2
    PE= mgh = mgdsinα
    I= 2r^2(mgdsinα- mv^2/2)/v^2

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