physics
posted by frank fred .
2 moles of an ideal gas at 20k changes from a pressure of 15 atm to 3 atm at constant temperature. Calculate the work done by the gas.

At constant temperature, P*V = constant and
P dV =  V dP = nRT/P*dP
Work done is therefore
Integral P dV = (nRT) dP/P
= (nRT) ln P2/P1
= nRT*ln(P1/P2)
= 2.0 moles*RT*ln5