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2 moles of an ideal gas at 20k changes from a pressure of 15 atm to 3 atm at constant temperature. Calculate the work done by the gas.

  • physics -

    At constant temperature, P*V = constant and
    P dV = - V dP = -nRT/P*dP

    Work done is therefore
    Integral P dV = -(nRT) dP/P
    = (-nRT) ln P2/P1
    = nRT*ln(P1/P2)
    = 2.0 moles*RT*ln5

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